(ln(x/2))^2-9=0

Solution for (ln(x/2))^2-9=0 equation:

D( x )

x/2 <= 0

x/2 <= 0

x/2 <= 0

1/2*x+0 <= 0 // - 0

1/2*x <= 0 // : 1/2

x <= 0/1/2

x <= 0

x in (0:+oo)

(ln(x/2))^2-9 = 0

t_1 = ln(x/2)

1*t_1^2 = 9 // : 1

t_1^2 = 9

t_1^2 = 9 // ^ 1/2

abs(t_1) = 3

t_1 = 3 or t_1 = -3

ln(x/2) = 3

ln(x/2) = ln(e^3)

x/2 = e^3

x/2-e^3 = 0

1/2*x-e^3 = 0 // + e^3

1/2*x = e^3 // : 1/2

x = (e^3)/1/2

x = 2*e^3

ln(x/2) = -3

ln(x/2) = ln(e^-3)

x/2 = e^-3

x/2-e^-3 = 0

1/2*x-e^-3 = 0 // + e^-3

1/2*x = e^-3 // : 1/2

x = (e^-3)/1/2

x = 2*e^-3

x in { 2*e^3, 2*e^-3 }